Question

To a 10mL HCl solution (pH = 3), 990mL NaCl solution is added. What is the pH of the resulting solution?

Answer 1

the acid becomes neutral the pH of the solution will be 7

Answer 2

Answer:

Explanation:

Volume of HCl = 10 mL or 0.01 L

Normality of HCl = 0.1 N

Number of gram-equivalents of HCl = Normality × Volume

= 0.1 × 0.01

= 0.001

Volume of solution = Volume of NaCl + Volume of HCl

= 990 + 10

= 1000 mL

= 1 L

As NaCl is salt it will not contribute towards the pH of the solution.

Normality of HCl in resulting solution = 0.001 / 1

= 0.001 N

pH = -log[H+]

= - log(0.001)

= 3