Question

To clear a competition, Sonu needs an average score of 90 in three exams. His score in first two exams are 93 and 85. What score must he get in the third exam to clear the competition? (a) 90 (b) 86 (c) 95 (d) 92

Answer 1

let the required score be x

average score=total marks obtained/no of exams

i.e. 90=93+85+x/3

i.e. 90=178+x/3

270=178+x

x=270-178=92

hence he has to score 92 marks to clear the exam

Answer 2

Given - Score in two exams

Find - Score in third exam

Solution - Average = sum of all scores/total number of scores

Total number of scores = 3

Let the score in third exam be x.

Sum of all scores = 93 + 85 + x

Sum of all scores = 178 + x

90 = (178 + x)/3

Performing multiplication

178 + x = 90*3

178 + x = 270

Performing subtraction

x = 270 - 178

x = 92

Sonu needs 92 marks to clear competition.