Question

to complete a work alone, father takes 5 days less than his son. if they do the work together it will be completed in 6days. find the time to complete the work each alone​

Answer 1

Answer:

The son completes the work alone in $5\frac{1}{2}$ day

The father completes the work along in $\frac{1}{2}$ day

The father is a lot faster than the son.

Step-by-step explanation:

F = S - 5

F + S = 6

(S - 5) + S = 6

2S - 5 = 6

2S = 11

S = 11/2 hours = $5\frac{1}{2}$ day

F = 11/2 - 5 = 11/2 - 10/2 = 1/2 day