Question

to construct a triangle which base is 4.5 cm vertical angle is 60° and another side is 3.5 cm.​

Answer 1

Answer:

the correct answer is 80 degree

Answer 2

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Steps of construction :

1. Draw a line segment AB = 4.5 cm.

2. Make an angle PAB = 60˚

3. Draw the perpendicular bisectors LM of AB.

4. Draw TA ⊥ AP at A.

5. Let LM and TA intersect at O.

6. Draw the circle with centre O and radius OA. Then any angle in the major segment, ∠PAB = 60˚ (Angle in alternate segment).

7. Let LM intersect AB at N, then N is the mid-point of AB. Taking N as centre and 3.5 cm radius, draw arcs intersecting the circle C, C’.

8.Join CA, CB and C’A and C’B. Then the required triangle is ABC or ABC’.

The obtained figure will be similar to the figure attached above.

$\textit{Hope this helps you}$

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