Question

To construct AABC where BC =4.7 cm, ZB=35°
and AB + AC=6 cm, a part of construction is done
for you. Follow the instructions and complete the
construction.
(i) Draw a perpendicular bisector of seg DC in the
given figure to intersect ray BD in point A.
(ii) Draw seg AC and complete A ABC.
D
6 cm
35°
B
4.7 cm
С

fast urgent...
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Answer 1

1) make an line segment BC of 4.7

2) then from angle B , make 35°

3) from angle B make an arc of 6cm ,then name it a point D and join DB and DC

4) take an perpendicular bisector of DC and name that point angle A , then join AC

your triangle has become .

Answer 2

Answer:

correct answer please sir and step by step explain