Question

to construct an equivalent triangle pqrs whose each side is 5.5 CM

Answer 1

An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.

The steps of construction are as follows.

(i) Draw a line segment BC of length 5.5 cm.



(ii) Taking point B as centre, draw an arc of 5.5 cm radius.



(iii) Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.



(iv) Join A to B and C.



ABC is the required equilateral triangle.


Hope this will help you..... ✌

Answer 2

hey mate here is ur answer
take BC base as 5.5 cms
then take ur protactor and ur scale then measure 5.5 cms in ur scale with protactor
keep it in the point B cut an arc
similarly in point C cut an arc
the arcs must have a similar point. like coinciding
then mark it as A
then join AB and AC.
now your construction is done
hope helped u mate pls mark as brainlist if it helps u and pls follow me if u want