Question

to
Convert the decimal number 4110
binary using
sum of powers of
method.​

Answer 1

Explanation:

THIS WILL BE HELPFUL IF YES THEN LIKE IT

Answer 2

Required Answer:-

Correct Question:

• Convert (41)₁₀ to its equivalent binary number.

Solution:

Conversion is given as:

$\dag \ \boxed{\begin{array}{c|c|c}\sf\underline{2}&\sf\underline{42}&\underline{\ \ }\\ \sf\underline{2}&\sf\underline{21}&\sf\underline{0}\\ \sf\underline{2}&\sf\underline{10}&\sf\underline{1}\\ \sf\underline{2}&\sf\underline{5}&\sf\underline{0}\\ \sf\underline{2}&\sf\underline{2}&\sf\underline{1}\\ \sf\underline{2}&\sf\underline{1}&\underline{0}\\ \sf&\sf0&\sf1\end{array}}$

Now, write the remainders from bottom to top.

$\sf\implies(41)_{10}=(1010\:10)_{2}$

Answer:

• (41)₁₀ = (1010 10)₂

Steps to solve:

1. Divide the number by 2.
2. Write the quotient and the remainder obtained.
3. Repeat the above two processes till the quotient is not 0.
4. Now, write the remainders from bottom to top.
5. Result obtained is the binary equivalent of the number.

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