To convert the pair of equations to pair of linear equations, the appropriate substitution is
1 point
p = 1/x, and q = 1/y
p = 1/(x-y), and q = 1/(x+y)
p = 1/(y-x), and q = 1/(x+y)
p = (x-y), and q = (x+y)
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Answer:
Lets assume
x
1
=p and
y
1
=q, both equations will become
2
p
+
3
q
=2
⇒3p+2q=12 ... (A)
3
p
+
2
q
=
6
13
⇒2p+3q=13 ...(B)
Multiply (A) by 3 and (B) by 2, we get
9p+6q=36
4p+6q=26
Subtracting these both, we get
5p=10
⇒p=2
⇒x=
p
1
=
2
1
∴q=
6
26−8
=3
⇒y=
q
1
=
3
1
Step-by-step explanation:
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