Question

To create a bulletin board, Maryann is planning to stretch fabric from burlap sacks over cardstock. She collects 6kg of burlap sacks. The area density of the burlap is 0.4 kg/m^2.What is the maximum area of the bulletin board that Maryann can make?

Answer 1

Answer:

Area = 15 square meter.

Step-by-step explanation:

Given : Maryann collects 6kg of burlap sacks. The area density of the burlap is $0.4 kg/m^2$.

To find : What is the maximum area of the bulletin board that Maryann can make?

Solution :

The area density is $A=0.4 kg/m^2$

which means,

For 1 square meter there is  0.4 kg of burlap sacks.

For 1 kg = $\frac{1}{0.4}$ sq.m

Now for the 6 kgs we will have :

$6\times\frac{1}{0.4}=\frac{60}{4}=15$

For 6 kg we need 15 square meter.

The maximum area of the bulletin board that Maryann can make is 15 sq.m

Answer 2

"Answer: The maxium area is $15 { m }^{ 2 }$

Given the area density of the burlap $= 0.4\quad \frac { kg }{ { m }^{ 2 } }$

For every 0.4 kg of fabric requires an area of $1 { m }^{ 2 }$

Therefore, the maximum area of the bulletin board that Maryann can make must be total burlap sacks by area density of the burlap

Such that the formula is,

$= (Total\quadburlap\quad sacks) / (Area \quad density \quad of \quad the\quad burlap)$

$=\quad \frac { 6 }{ 0.4 } \quad =\quad 15{ m }^{ 2 }$"