Question

To determine acceleration due to gravity, the time of 20 oscillations of a simple pendulum of length

100 cm was observed to be 40 s. calculate the value of g and maximum percentage error in the

measured value of g.​

Answer 1

Answer:

9.85 m/s²

Explanation:

we know that

T = 2π √(L/g)

or by rearranging we get

g = 4π2L / T2

now, here

L = 100 cm = 1m

T = 40/20s = 2s

thus,

g = (4π2x1)/ 22 = 39.4384 / 4

or

g = 9.85 m/s2

the corresponding error equation would be

Δg/g = ΔL/L + 2(ΔT/T)

or

Δg = g.[ΔL/L + 2(ΔT/T)]