to diveidw a line segment ABnin teh ratio 5 to 6 draw a ray such thay it BAX is an acute angkes answer it
Answers
Answer:
Step-by-step explanation:
Given, a line segment AB in the ratio 5:7
A:B = 5:7
Steps of construction:
1. Draw a ray AX, an acute BAX.
2. Draw a ray BY AX,
ABY = BAX.
3. Now, locate the points A1,A2,A3,A4 and A5 on AX and B1,B2,B3,B4,B5 and B6 (Because A:B = 5:7)
4. Join A5B6.
A5B6 intersect AB at a point C.
AC:BC= 5:6
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Answer:
Correct Option : (a)
Explanation:
In the figure , segment Aab of given lenght is divided into 2 parts of ratio 5:6 in following steps:
(i) Draw a line segment AB of given length.
(ii) Draw an acute amgle BAX a shown in figure either upside or down side.
(iii) Draw angle ABY = BAX on other side of AX, that is, down side.
(iv) Divide AX into 5 equal parts by using compass.
(v) Now join A5 and B6 which meet AB at P. P dividea AB in ratio AP:PB = 5:6.
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