prove that the square of any positive integer is the form of 5q ,5q+1 ,5q+4 Of some positive integers
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Step-by-step explanation:
a=bq+r where 0 is less than or equal to r and r is less than b
b=5 and r=0,1,2,3,4
Case 1 : r=0
a=bq+r
=5q+0
SOBS(square on both sides)
=(5q)²
=25q²
=5q(5q)
so 5q is a multiple of number and is form of 5q
case 2: r=1
a=bq+r
=5q+1
SOBS
(5q+1)²
apply (a+b)²=a²+2ab+b²
25q²+2(25q)(1)+1²
25q²+50q+1
5q(5q+10)+1
So 5q is a multiple of the number and is of the form 5q+1
like this do till r=4 and you will get the number to be in the form 5q,5q+1,5q+4
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hey you mate I have given you answer in the pic
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