To divide a line segment AB in the ratio 3:7, what is the minimum number of points marked on a ray AX at equal distances
Answers
Given : A line segment AB Divided in the ratio of 3 : 7
To find : Minimum number of points marked on a ray AX at equal distances
Solution:
Total number of points required are 3 + 7 = 10
Step 1 : Draw given line segment AB
Step 2 : Draw a Ray AX at an acute angle at AB
Step 3 : Mark 10 point at equal distances starting from A
Step 4 : Draw a line segment joining 10th point with B
Step 5 : Draw a line parallel to line segment drawn in step 4 such that it passes through 3rd point on ray AX and intersect AB at C
AC : CB = 3 : 7
Minimum 10 points are required to be marked on a ray AX at equal Distance to divide a line segment AB in the ratio 3 : 7
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Answer:
12 is the correct ans