to divide a line segment ratio 3:7 first a ray AX is drawn so that angle BAX is an acute angle at equal distances point are marked on the ray AX such that the minimum number of these point is (draw a figure and steps of construction) plz guys send fast.
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The line is to be divided in 3:4
Let the parts be 3x and 4x
3x=x+x+x
So 3x has 3 equal parts
Similarly 4x=x+x+x+x
So 4x has four equal parts.
So a total of 7 points are needed.
Option C is correct.
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