Question

To do a certain work B would take three times as long as A and C together and C takes twice as A and B together . The three men together complete the work in 10 days . How long would each take separately ?

Answer 1

Answer:

24 days

Explanation:

According to question,

Since we know, efficiency of persons will remain same. so we will balance it.

Now we can see, B's efficiency is 3 units and C's is 4 units and total is 12 units. So A's efficiency is 12−4−3=5 units

Total work = 10days×12units

A can complete separately in

T.W 120

___________ = ____ = 24 days

Efficiency of A. 5

I hope this answer has satisfied you

If it have satisfied to you mark me as brainliest

And follow me ☺️☺️☺️☺️☺️☺️☺️☺️

Answer 2

$\huge\mathtt\red{Question:- }$

→ To do a certain work B would take three times as long as A and C together and C takes twice as A and B together . The three men together complete the work in 10 days . How long would each take separately ?

$\huge\mathtt\red{To \; Find :- }$

→ How long would each take separately to complete the work

$\huge\mathtt\red{Solution:- }$

→ 3 Times B's daily work = ( A + C ) 's daily work

→ Add B's daily work both side

→  4 times B's daily work = ( A + B + C )'s daily work

   $\sf = \dfrac{1}{10}$

$\sf \rightarrow B's \; daily\;work\;= \dfrac{1}{40}$

→ Also 2 times C's daily work = ( A + B )'s daily work

→ Add C's work both side

$\sf \rightarrow 3\;times\;C's\;daily\;work\;=\;\dfrac{1}{10}$

$\sf \rightarrow C's\;daily\;work\;=\;\dfrac{1}{30}$

$\sf \rightarrow A's\;daily\;work\;=\dfrac{1}{10} - \bigg\{ \dfrac{1}{40}+\dfrac{1}{30}\bigg\}$

$\sf \rightarrow \dfrac{1}{10} - \dfrac{7}{120}$

$\sf \rightarrow \dfrac{1}{24}$

∴  A took = 24 days

   B took = 40 days

   C took = 30 days

___________