To do a work 3 men takes 5 days less than 9 boys.3 boys and 2 men can do the work in 6 days. If man works at half efficiency and boy works at twice efficiency then in how many days the work will be completed by one man and one boy?
Answers
Given : To do a work 3 men takes 5 days less than 9 boys . 3 boys and 2 men can do the work in 6 days
To find : in how many days the work will be completed by one man and one boy
Step-by-step explanation:
Let say Man do work in 1 day = M
& Boy do work in 1 Day = B
.3 boys and 2 men can do the work in 6 days.
=> Total Work = 3 * 6 * B + 2 * 6 * M
= 18B + 12 M
Days taken by 9 Boys = (18B + 12M)/9
Days taken by 3 Men = ( 18B + 12 M)/3 = 6B + 4M
6B + 4M = (18B + 12M)/9 - 5
=> 54B + 36M = 18B + 12M - 45
=> 36B + 24M = -45
=> 18B + 12M = -45/2
Work = - 45/2
Work can not be - ve
Hence there is some mistake in data
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