Question

To emphasize the importance of fitness, K V 1 hindan has made one mandatory period of sports daily. Currently school is having facilities only for football and basketball, there are 4 y2 + y -8 students of class VIII, if 2 y + 16 students play football, how many opt basketball? It is compulsory for each student to play one game.​

Answer 1

$Total \: number \: of \: students \:of \:class$

$VIII = 4y^{2} + y - 8\: --(1)$

$Number \:of \: students \: who \: play$

$Football = 2y + 16 \: ---(2)$

$Number \:of \: students \: who \: opt$

$basketball = (1) - (2)$

$= 4y^{2} + y - 8 - ( 2y + 16 )$

$= 4y^{2} + y - 8 - 2y - 16$

$= 4y^{2} - y - 24$

Therefore.,

$\red{Number \:of \: students \: who \: opt}$

$\red{ basketball}\green{ =4y^{2} - y - 24}$

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Answer 2

y90 ans

solve 4y - 2 =9

80 diving 90

y= 90