Math, asked by ready64, 6 months ago

To factorise m^2-4m+33​

Answers

Answered by Anonymous
178

\huge{\bold☘}\mathfrak\pink{\bold{\underline{{ ℘ɧεŋσɱεŋศɭ}}}}{\bold☘}

\red{\bold{\underline{\underline{❥Question᎓}}}}To factorise m^2-4m+33

\huge\tt\underline\blue{「Answer」</p><p> }

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 {m}^{2}  - 4 m + 33

Here we use quadratic formula to find out the roots:-

\bold{Here\: ,a=1\: ,b=-4 &amp; c=33}

 ⟹m =  \frac{ - b ± \sqrt{ {b}^{2}  - 4ac}  }{2a}

 ⟹ m=  \frac{ - ( - 4)±\sqrt{ {( - 4)}^{2}  - 4(1)(33)}  }{2(1)}

 ⟹m=  \frac{4± \sqrt{16 - 132} }{2}

 ⟹m =  \frac{4± \sqrt{ - 116} }{2}  =  \frac{4±2 \sqrt{ - 29} }{2}

 ⟹m =  \frac{2(2± \sqrt{ - 29} )}{2}  = 2± \sqrt{29i}

\bold{Here\: is\: your\: answer}

i(we say iota is placed of -ve sign whenever inside the root value so we simply replace negative sign by placing iota instead of negative sign inside roots)

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