To fill a cistern,pipe p q and r take 20, 15 and 12. the time in mins that 3 pipes fill in cistern is
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Here it is given that pipe p can fill the cistern in 20 mins, pipe q in 15 mins and pipe r in 12 mins. To find out the actual capacity of the cistern, we need to take the LCM of all the three i.e 20,15 and 12 and we get the LCM as 60. Therefore the actual capacity of the cistern is 60(let's assume litres as the unit is not mentioned). Now, let's find out how much will each pipe fill the cistern in 1 min.
If in 20 mins pipe p can fill 60ltrs
Then in 1 min it can fill 60/20 ltrs=3ltrs
Similarly in 1 min pipe q can fill 60/15 ltrs=4 ltrs
And pipe r can fill 60/12ltrs= 5ltrs.
Therefore in 1 min the cistern will be filled by (p in 1 min)+(q in 1 min)+(r in 1 min)= (3+4+5)ltrs =12 ltrs
Now,
Time taken in fill 12 ltrs=1 min
Therefore,
Time taken to fill 60 ltrs=60/12(apply unitary method) =5 mins
Therefore, all the three pipes can fill the cistern together in 5 mins.
If in 20 mins pipe p can fill 60ltrs
Then in 1 min it can fill 60/20 ltrs=3ltrs
Similarly in 1 min pipe q can fill 60/15 ltrs=4 ltrs
And pipe r can fill 60/12ltrs= 5ltrs.
Therefore in 1 min the cistern will be filled by (p in 1 min)+(q in 1 min)+(r in 1 min)= (3+4+5)ltrs =12 ltrs
Now,
Time taken in fill 12 ltrs=1 min
Therefore,
Time taken to fill 60 ltrs=60/12(apply unitary method) =5 mins
Therefore, all the three pipes can fill the cistern together in 5 mins.
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