to find a point p on a line segment ab=6, such that ap÷ab=2÷5 ,in which ratio the line segment ab is divided
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Hey there ✋✋,
Here's the answer:-
I hope you meant AP : AB = 2:5
If yes then Let AP = 2x cm and AB = 5x cm
We know already that AB = 6cm
=> 5x = 6cm
=> x = 6cm/5 = 1.2 cm
So, AP = 2x = 2.4 cm
PB = AB - AP = 6.0-2.4 = 3.6 cm
So, ratio by which line is divided = 1.2 : 3.6 = 1.2×10:3.6×10 = 12:36 = 1:3
So, finally the ratio is 1:3
HOPE IT HELPS ☺
PLEASE MARK BRAINLIEST
Here's the answer:-
I hope you meant AP : AB = 2:5
If yes then Let AP = 2x cm and AB = 5x cm
We know already that AB = 6cm
=> 5x = 6cm
=> x = 6cm/5 = 1.2 cm
So, AP = 2x = 2.4 cm
PB = AB - AP = 6.0-2.4 = 3.6 cm
So, ratio by which line is divided = 1.2 : 3.6 = 1.2×10:3.6×10 = 12:36 = 1:3
So, finally the ratio is 1:3
HOPE IT HELPS ☺
PLEASE MARK BRAINLIEST
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