To find a point p on the line segment ab=6 cm such that ap:ab=2:5 in which ratio does the line segment ab is divided by p
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Hi there......
AB=6 cm
AP:AB = 2:5
Let AP:AB = 2x:5x
AP=2x
AB=5x
We know that AP + PB = AB
2x + PB = 5x
PB = 5x - 2x = 3x
Therefore ratio of AP:PB = 2x : 3x
There P divides AB in the ratio 2:3
Please comment if you have any doubt...
And please mark my answer as the brainliest!!!
AB=6 cm
AP:AB = 2:5
Let AP:AB = 2x:5x
AP=2x
AB=5x
We know that AP + PB = AB
2x + PB = 5x
PB = 5x - 2x = 3x
Therefore ratio of AP:PB = 2x : 3x
There P divides AB in the ratio 2:3
Please comment if you have any doubt...
And please mark my answer as the brainliest!!!
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