Question

to find the ratio in which point p (k,7) devides the segment joining A (8,9) nad (1,2) . Please Answer​

Answer 1

Answer:

So, the required ratio is 2 : 5.

Answer 2

Using the section formula, if a point (x,y) divides the line joining the points (x  

1

​

,y  

1

​

) and (x  

2

​

,y  

2

​

) in the ratio m:n, then  

(x,y)=(  

m+n

mx  

2

​

+nx  

1

​

 

​

,  

m+n

my  

2

​

+ny  

1

​

 

​

)

Let the ratio be x: 1.  

Using the section formula,

k=  

x+1

1x+1×8

​

 

⇒kx+k=x+8(1)

Also,7=  

x+1

2x+9

​

 

⇒7x+7=2x+9

⇒5x=2

⇒x=  

5

2

​

 

So, the required ratio is 2 : 5.  

Putting this value of x in (1) we get

k(  

5

2

​

+1)=  

5

2

​

+8

⇒  

5

7

​

k=  

5

42

​

 

⇒k=6

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