Question

To find the sum of squares of the first 100 natural numbers in python

Answer 1

Answer:

The task is to find 1^2 + 2^2 + 3^2 + ….. + 100^2.

def squaresum(n) :

sm = 0

for i in range(1, n+1) :

sm = sm + (i * i)

return sm

n = 100

print(squaresum(n))

Answer 2

Answer:

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Explanation:

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