Question

To find the value of g using simple pendulum of t = 2 sec and l = 50 cm. find the permissible error?

Answer 1

the formula here use is
$g = 4\pi ^{2}( l \div t { }^{2} )$

$4 \times (3.14) {}^{2} (50 \div 4) \\ = 492.98$
ans =492.98 cm/s^2