Question

to find the100 term of ahe AP 5,8,11,14 complete the following activity​

Answer 1

Answer:

The given sequence is 5, 8,11,14,… Here, t1 = 5, t2 = 8, t3 = 11, t4 = 14 ∴ t2 – t1 = 8 – 5 = 3 t3 – t2 = 11 – 8 = 3 t4 – t3 = 14 – 11 = 3 ∴ t2 – t1 = t3 – t2 = t4 – t3 = 3 = d = constant The difference between two consecutive terms is constant ∴ The given sequence is an A.P

. ii. tn = a + (n – 1)d ∴ t100 = 5 + (100 – 1)3 …[∵ a = 5, d = 3] = 5 + 99 × 3 = 5 + 297 ∴ t100 = 302 ∴ 100th term of the given A.P. is 302.

Answer 2

Answer:

here we have an AP 5,8,11,14

from the AP we get a = 5 , d = 8-5=3

we know that

an = a + ( n -1 ) d

= 5 +(100-1)3. (given, n=100)

=5+99*3

=5+287 =292