To get 50 points... heres the question
PROOF OF PYTHAGORAS THEOREM BY DIFFERENT METHODS
(AT LEAST 5 METHODS)
PLZ ITS URGENT...
Answers
Answered by
5
Given : A right ΔABC right angled at B
To prove : AC2 = AB2 + BC2
Construction : Draw AD ⊥ AC
Proof : ΔABD and ΔABC
∠ADB = ∠ABC = 90°
∠BAD = ∠BAC (common)
∴ ΔADB ∼ ΔABC (by AA similarly criterion)
⇒ AD × AC = AB2 ...... (1)
Now In ΔBDC and ΔABC
∠BDC = ∠ABC = 90°
∠BCD = ∠BCA (common)
∴ ΔBDC ∼ ΔABC (by AA similarly criterion)
⇒ CD × AC = BC2 ........ (2)
Adding (1) and (2) we get
AB2 + BC2 = AD × AC + CD × AC
= AC (AD + CD)
= AC × AC = AC2
∴ AC2 = AB2 + BC2
To prove : AC2 = AB2 + BC2
Construction : Draw AD ⊥ AC
Proof : ΔABD and ΔABC
∠ADB = ∠ABC = 90°
∠BAD = ∠BAC (common)
∴ ΔADB ∼ ΔABC (by AA similarly criterion)
⇒ AD × AC = AB2 ...... (1)
Now In ΔBDC and ΔABC
∠BDC = ∠ABC = 90°
∠BCD = ∠BCA (common)
∴ ΔBDC ∼ ΔABC (by AA similarly criterion)
⇒ CD × AC = BC2 ........ (2)
Adding (1) and (2) we get
AB2 + BC2 = AD × AC + CD × AC
= AC (AD + CD)
= AC × AC = AC2
∴ AC2 = AB2 + BC2
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Answered by
3
Hey mate ^_^
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Answer:
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Given : A right ΔABC right angled at B
To prove : AC^2 = AB^2 + BC^2
Construction : Draw AD ⊥ AC
Proof : ΔABD and ΔABC
∠ADB = ∠ABC = 90°
∠BAD = ∠BAC (common)
∴ ΔADB ∼ ΔABC (by AA similarly criterion)
=> AD/AB = AB/AC
⇒ AD × AC = AB^2 ...... (1)
Now In ΔBDC and ΔABC
∠BDC = ∠ABC = 90°
∠BCD = ∠BCA (common)
∴ ΔBDC ∼ ΔABC (by AA similarly criterion)
=> CD/BC = BC/AC
⇒ CD × AC = BC^2 ........ (2)
Adding (1) and (2) we get
AB^2 + BC^2 = AD × AC + CD × AC
= AC (AD + CD)
= AC × AC = AC^2
∴ AC^2 = AB^2 + BC^2
#Be Brainly❤️
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Answer:
=======
Given : A right ΔABC right angled at B
To prove : AC^2 = AB^2 + BC^2
Construction : Draw AD ⊥ AC
Proof : ΔABD and ΔABC
∠ADB = ∠ABC = 90°
∠BAD = ∠BAC (common)
∴ ΔADB ∼ ΔABC (by AA similarly criterion)
=> AD/AB = AB/AC
⇒ AD × AC = AB^2 ...... (1)
Now In ΔBDC and ΔABC
∠BDC = ∠ABC = 90°
∠BCD = ∠BCA (common)
∴ ΔBDC ∼ ΔABC (by AA similarly criterion)
=> CD/BC = BC/AC
⇒ CD × AC = BC^2 ........ (2)
Adding (1) and (2) we get
AB^2 + BC^2 = AD × AC + CD × AC
= AC (AD + CD)
= AC × AC = AC^2
∴ AC^2 = AB^2 + BC^2
#Be Brainly❤️
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