To get maximum current in a resistance of 3 ohms, one can use n rows of m cells (connected in series) connected in parallel. If the total number of cells is 24 and the internal resistance of a cell is 0.5 ohms then(a) m = 12, n = 2(b) m = 8, n = 3(c) m = 2, n = 12(d) m = 6, n = 4
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here's the answer....
To get maximum current in a resistance of 3 ohms, one can use n rows of m cells (connected in series) connected in parallel. If the total number of cells is 24 and the internal resistance of a cell is 0.5 ohms then(a) m = 12, n = 2(b) m = 8, n = 3(c) m = 2, n = 12(d) m = 6, n = 4
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Given:
Resistance
Number of rows
Number of cells in one row
Total number of cells
Internal resistance of a cell
To Find: The value of and
Solution:
The equivalent potential for '' number of cells connected in series combination is given as:
Where, potential of each cell, internal resistance of each cell
If the total potential of the cells in the series is and total internal resistance is , then,
... (i)
The potential for a number of cells connected in parallel combination is given as:
If the total potential is and total internal resistance is , then,
... (ii)
As 24 cells are to be connected in rows of cells
From Ohm's law, we have,
... (iii)
In order to get maximum current, the value of should be minimum.
It will be minimum for ... (iv)
Therefore, the maximum current is given by
Putting the values of and in equation (iv), we have,
Thus, and
Hence, the value of m and n is 12 and 2 respectively. Thus, the correct option is (a) m = 12, n = 2.
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