Question

to go from town A to town B a plane must fly about 1780 km at an angle of 30 west of north.how far north of A is B

Answer 1

This motion can be represented on a right angled triangle.

The point A and B lie on the same plane thus AB forms the length of the base of this triangle.

Since Point C is at an angle 30° from A, it forms the hypotenuse.

The length of the hypotenuse is :

= 1780Km.

We want to get length from North of A where B is.

This is the length CB.

Using trigonometric ratios we have :

Sin 30° = BC / 1780

BC = 1780 Sin 30°

BC = 890 km

Answer 2

Answer:

A is $890$ Km north of B

Explanation:

• Here in the figure given below we can see ABC makes a right angles triangle.
• So the hypotenuse is given as AB = $1780$ Km
• Now the distance of A from north of B is given by CA
• Using trigonometric ratios we have :
  $Sin 30^0 = \frac{CA}{1780}\\CA = 1780 * Sin 30^0\\CA = 1780 * \frac{1}{2}\\CA=890$
• Hence A is $890$ Km north of B