Question

to How many grams of H3po4is required completely neutralize 60g of NaOH ​

Answer 1

Explanation:

120 g of NaOH (molar mass 40 g/mol) =

40g/mol

120g

=3moles

3NaOH+H

3

PO

4

→Na

3

PO

4

+3H

2

O

3 moles of NaOH will react with 1 mole of H

3

PO

4

.

Molar mass of H

3

PO

4

= 98 g/mol.

Mass of H

3

PO

4

=1mol×98g/mol=98mol

Answer 2

Answer:

Reffer Above the attachment