Question

to locate a point Q on line segment AB such that BQ=5/7×AB. what is the ratio of line segment in which AB is divided?​

Answer 1

Answer:

P divides of the line AB=2:3

Q divides of line AB=3:4

The distance between P and Q=2 cm

we have to find the length of AB=?

AB=AP+PB=2x+3x=5x

Or

AB=AQ+QB=3x+4x=7x

LCM of 5x and 7x=35x=AB

AP+PQ=AQ

2x+2=3x

x=2,

The length of AB=35×2 cm=70 cm

Step-by-step explanation:

I hope this helps you.