Question

To maintain a rotor to uniform angular speed of 200 rad s⁻¹, an engine needs to transmit to torque of 180 N m. What is the power required by the engine? [Note: uniform angular velocity in the absence of friction implies zero torque. In practice, applied torque is needed to counter frictional torque) Assume that the engine is 100% efficient.

Answer 1

Hello mate,

● Answer-
P = 36 kW

● Explaination-
# Given-
τ = 180 Nm
ω = 200 rad/s

# Solution-
Here, engine is 100% efficient so we'll consider zero power loss.

Power of the rotor is given by -
Power = Torque × angular velocity
P = τ × ω
P = 180 × 200
P = 36000 Watt
P = 36 kW

Therefore, power of the rotor is 36 kW.

Hope this is helpful...