Question

To make a decimolar solution in 100ml how many grams of dibasic acid having molecular mass 200gm/mole should be added?​

Answer 1

Answer:

Explanation:

n-factor of a dibasic acid = 2

Molarity = Normality/n-factor = 0.1/2 = 0.05

Number of moles = Molarity x Volume(in litres) = 0.05 x 0.1 = 0.005

→ Number of moles = given weight / molecular weight

→ 0.005 = given weight / 200

→ given weight = 0.005 x 200 = 1 gram

Thus, 1 gram of Dibasic acid should be present in 100ml of aqueous solution to prepare a 0.1N solution.

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