Question

to make a open fish tank,a glass sheet of 2mm guage is used . the outer length,breadth and height of tank are 60.4 cm ,40.4cm,40.2cm respectively. how much maximum volume of water will be contained in it ?

Answer 1

$60.4 + 40.4 + 40.2 = 141.0 \\ 141 \times 2 = 282$

Answer 2

Answer:  Maximum Volume will be 96000 cm³.

Step-by-step explanation:

Since we have given that

Length of tank = 60.4 cm

Breadth of tank = 40.4 cm

Width of tank = 40.2 cm

Since, glass sheet of 2 mm = 0.2 cm guage is used.

so, it becomes

New length becomes = 60.4-0.2-0.2=60 cm

New breadth becomes = 40.4-0.2-0.2=40 cm

New height becomes = 40.2- 0.2 = 40 cm

So, Maximum volume of water that will be contained in it is given by

$Length\times breadth\times height\\\\=60\times 40\times 40\\\\=96000\ cm^3$

Hence, Maximum Volume will be 96000 cm³.