Question

To obtain formula for the sum off squares of first n natural number​

Answer 1

Answer:

Sum of: Formula

Squares of two numbers x2 + y2 = (x+y)2-2ab

Squares of three numbers x2 + y2+z2 = (x+y+z)2-2xy-2yz-2xz

Squares of first 'n' natural numbers Σn2 = [n(n+1)(2n+1)]/6

Squares of first even natural numbers Σ(2n)2 = [2n(n+1)(2n+1)]/3

Answer 2

Answer:

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