Question

to obtain the solution of quadratic equation x^2+4x+3=0 by completing the square geometrically maths project please help me to do this project otherwise I will lose marks please​

Answer 1

Step-by-step explanation:

x²+4x+3= 0

x²+3x+x+3= 0

x(x+3)+1(x+3)= 0

(x+3)(x+1)= 0

either X+3= 0 or X+1 = 0

So, if X+3= 0

then, X= -3

also, if X+1= 0

then, X= -1

thus, the possible values for x are either -3 or -1