To prove root3 is an irrational number
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- theorem 1.3 is if a prime number divides a square ,then it divides a.
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let us suppose that √3 is rational and =a/b where a and b are coprime
√3=a/b
b√3=a
squaring both sides
3b²=a²
therefore a² is divisible by 3 so a is also divisible by 3
let us take a=3c
3b²=9c²
b²=3c
therefore b² is divisible by 3 so b is also divisible by three
now we got to know that a and b must be having atleast three as their common factor but a and b are coprime
this contradiction is arised from our incorrect assumption that √3 is rational
so we conclude that √3 is irrational
ashwin2819:
Thanks
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