To prove:(sin a +cos a)(tan a +cot a)=sec a +cosec a
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Step-by-step explanation:
(sinA+cosA)(tanA+cotA)
=(sinA+cosA)(sinA/cosA+cosA/sinA)
=(sinA+cosA)(1/sinAcosA)
=(sinA+cosA)/sinAcosA
=sinA/sinAcosA+cosA/sinAcosA
=1/cosA+1/sinA
=secA+cosecA
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