to prove that ncr is an interger
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0Cr is an integer, for all r (1 if r=0, and zero otherwise). Suppose that for a given n, all the nCr are integers, then since {n+1}Cr = nCr + nC{r-1} it follows that the {n+1}Cr are integers for all r. Hence, by induction, nCr is an integer for all n and all r.
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