Question

to prove that of trigonometry

Answer 1

b^2 x^2 - a^2 y^2


put x = asecv
y = b tanv

b^2 a^2 sec^2 v - a^2 b^2 tan^2v

b^2 a^2( sec^2 v- tan^2v)

b^2 a^2

Answer 2

Answer:

Step-by-step explanation:

$b^2(a^2 sec^2v)-a^2(b^2tan^2v)\\b^2a^2(sec^2-tan^2)\\a^2b^2(1)\\a^2b^2$