Question

To. prove. that weight of an object on the moon is 1/6th the weight of the object on the earth.​

Answer 1

AnswEr:

Weight = mass $\times$ acceleration due to gravity

$\qquad \tt \: w = mg$

• Value of g on earth, $\tt{g}_{e}$ = 9.8 m $\sf{s}^{-2}$

• Value of g on moon, $\tt{g}_{m}$ = 1.6 m $\sf{s}^{-2}$

$\qquad \tt \frac{g_m}{g_e} = \frac{1.6}{9.8} = \frac{1}{6}$

$\rightarrow \tt \frac{weight \: on \: moon}{weight \: on \: earth} \\ \\ \rightarrow \tt \frac{mg_m}{mg_e} = \frac{1}{6}$

$\star$ $\text{Weight\:on\:moon=}$ $\tt\dfrac{1}{6}$$\text{(weight\:on\:earth)}$

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Acceleration due to gravity :

The acceleration of any mass near the surface of the earth due to gravitation of earth ( gravity ) is called acceleration due to gravity (g).

= Its SI unit is same as Acceleration i.e m/s².