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ANSWER :-
Using g = GM/R^2
Where G is Universal Gravitational Constant (6.67 * 10^-11 N-m^2/Kg^2)
M is Mass of earth (6*10^24 Kg)
R is Radius of earth (6.4*10^6 m)
By plugging in the respective values in the above expression
g = (6.67 * 10^-11 N-m^2/Kg^2 ) x (6*10^24 Kg) / (6.4*10^6 m)^2
After simplification we will get g around 9.8 m/ s^2.
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Using g = GM/R^2
Where G is Universal Gravitational Constant (6.67 * 10^-11 N-m^2/Kg^2)
M is Mass of earth (6*10^24 Kg)
R is Radius of earth (6.4*10^6 m)
By plugging in the respective values in the above expression
g = (6.67 * 10^-11 N-m^2/Kg^2 ) x (6*10^24 Kg) / (6.4*10^6 m)^2
After simplification we will get g around 9.8 m/ s^2.
PLEASE MARK AS BRAINLIEST
PLEASE MARK AS BRAINLIEST
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