Math, asked by jcpos7501, 9 months ago

To rationalise the denominator of 1/ root a+b

Answers

Answered by Bharti05090
3

Answer:

1/√a+b

= a-b/a^2-b^2

= a-b/(a+b)x(a-b)

1/a-b * a+b/a-b

= a+b/(a-b)^2

Step-by-step explanation:

1- rationalised denominator by a-b

2- using identity a^2-b^2

Answered by Prannava
0

Answer:

1/√a+b

= a-b/a^2-b^2

= a-b/(a+b)x(a-b)

1/a-b * a+b/a-b

= a+b/(a-b)^2

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