Question

To show that in a freely falling object from rest, from a height h and a velocity v, the kinetic energy = to the potential energy (take g=10)

Answer 1

This will happen when,

mgh =(mv^2)/2

2gh =v^2

2gh = 2g(H-h) (H is the total higher from the ground)

gh =gH -gh

h=H/2

At exactly mid way of the