Question

To solve mathematical problem. Find the equation of tangent and normal to y=3xsquare-4x+7 at ptoint whose value is 7

Answer 1

y= 3x²-4x+7=7

3x²−4x+7−7=0

3x²-4x=0

D=b²−4ac

D=(−4)−4(3)(0)

D=16-12(0)

D=16−0

D=16