to solve the following equation by determinant y+2x-19=0,2x-3y+3=0 find D,Dx,Dy by cramers rule
Answers
Step-by-step explanation:
y+2x-19=0 , 2x -3y+3=0
2x+y=19 , 2x-3y= -3
2x+y=19 ............ (1)
2x-3y=-3 ............. (2)
D = 2 1 = 2×(-3) - 2×1
= -6 - 2
2 -3 = -8
D = -8
D of x = 19 1 =19×(-3) - (-3)×1
= -57 +3
-3 -3 = -54
D of x = -54
D of y = 2 19 = 2×(-3)- 2×19
= -6 - 38
2 -3 = -44
D of y = -44