Question

to solve the quadratic equation x2 + 6x+5=0 by using formula method​

Answer 1

Answer:

${x}^{2} + 6 x+ 5 \\ \\ {x}^{2} + 5x + x + 5 \\ \\ x(x + 5) + 1(x + 5) \\ \\ (x + 1)(x + 5) \\ \\ take \\ \\ x + 1 = 0 \: \: \: and \: x + 5 = 0 \\ \\ x = - 1 \: \: \: \: x = - 5 \\ \\ hence \: the \: value \: of \: x = - 1 \: and \: - 5$

Answer 2

The values of x are -1 and -5.

Step-by-step explanation:

The quadratic equation is

$x^2+6x+5=0$

Comparing this equation with $ax^2+bx+c=0$

a = 1, b = 6, c = 5

The quadratic formula is given by

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substituting the values

$x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \:5}}{2\cdot \:1}\\\\\=frac{-6\pm\sqrt{16}}{2}\\\\=\frac{-6\pm4}{2}\\\\\frac{-6+4}{2},\frac{-6-4}{2}\\\\=-1,-5$

The values of x are -1 and -5.

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