To solve x + y =3 ; 3x - 2y - 4 = 0 by determinant method find D
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Answered by
56
x+y=3 is a first equation
3x-2y-4=0 is a second equation, it modified to
3x-2y=4
multiple 3 with first equation, we get
3x+3y=9
now subtract these equations
we get 5y=13
y=13/5
substitute 13/5 in first equation, we get,
x=2/5
3x-2y-4=0 is a second equation, it modified to
3x-2y=4
multiple 3 with first equation, we get
3x+3y=9
now subtract these equations
we get 5y=13
y=13/5
substitute 13/5 in first equation, we get,
x=2/5
Answered by
15
My answer comes to be x=14&y=5/3
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