to the numerator of a fraction is 3 less
thom its denommator . If 2 is added to
both the numerator & the denominator
then the sum of the were fraction & the
original fraction is 29÷30 find the original fraction
Answers
Answer:
86/89
Step-by-step explanation:
Here, we take D as denominator and N as Numerator.
We are given that N is 3 less than D
We'll take D as x, and value of N will be x - 3
D = x
N = x - 3
Original Fraction: x - 3 / x
Then, 2 is added to both N and D resulting in one more fraction
D2 = x + 2
N2 = x - 3 + 2
So, new fraction: x - 3 + 2 / x + 2 => x - 1 / x + 2
Sum of two fractions:
x - 3 + x - 1 / x + x + 2 => 2x - 4 / 2x + 2 => 2 ( x - 2 ) / 2 ( x + 1 ) => x - 2 / x + 1
We are also given that sum of fractions is equal to 29 / 30
So, here we get an equation
x - 2 / x + 1 = 29 / 30
By Cross Multiply
( x - 2 ) * 30 = ( x + 1 ) * 29
=> 30x - 60 = 29x + 29
=> 30x - 29x = 29 + 60
=> x = 89
Here we got the value of x, we put it in the original fraction:
x - 3 / x
=> 89 - 3 / 89
=> 86 / 89
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