Question

TO
V.
Prove that:
Diagonals of a parallelogram bisect each other.
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let ABCD be a parallelogram

Diagonals AC and BD intersect at O

In triangles AOD and COB,

Angle DAO=Angle BCO (alternate interior angles)

AD=CB

Angle ADO=Angle CBO (alternate interior angles)

Hence,Triangle AOD is congruent to Triangle COB (ASA)

So,AO=COand OD=OB (C.P.C.T)

Thus,the diagonals of parallelogram bisect each other.