Question

To verify the abgebraic identity (a-b)²=a²-2ab +b²
please help​

Answer 1

Answer:

We take distinct values of a and b.

Step 1: Paste the white paper on the cardboard. Draw a square ABCD of side a units.

Step 2: Calculate the value of (a – b). On the glazed paper, construct two rectangles each having length (a-b) units and breadth b units. Also, construct a square of side b units.

Step 3: Cut the square and the two rectangles from the glazed paper and place them on the white paper. Arrange these inside the square ABCD as shown in Figure 111.1

We observe that the area of square AEFH=(a-b)² square units.

Also, area of square AEFH

= area of square ABCD – area of rect. EBGF – area of rect. HFID – area of square FGCI

i. e., (a-b)² = a²-(a-b)b-(a-b)b-b²

=> (a-b)² =a²-ab+b²-ab+b²-b²

=> (a-b)² = (a² – 2ab+b²).

Answer 2

Answer:

(a-b)²=(a-b)(a-b)

        = a²-ab-ab+b²

        = a²-2ab+b²